Question

Letra A de preferencia por favor

Answer 1

Vamos fazer as bases ficarem iguais:

$\frac{3^{3} }{2^{3} } =(( \frac{3^{} }{2 })^{3})^{3x+1}\\\\ ( \frac{3^{} }{2 })^{9x+3}\\\\\frac{2^{2} }{3^{2} } = (( \frac{3^{} }{2 })^{-2})^{x}\\\\ ( \frac{3^{} }{2 })^{-2x}\\\\( \frac{3^{} }{2 })^{9x+3}= ( \frac{3^{} }{2 })^{-2x}$

Cortando as bases e igualando os expoentes:

9x +3 = -2x

9x+2x = -3

11x = -3

x = -3/11