Question

lei que reresenta a inversa da função f(x)= 2x+1 é: *

a) f^(-1) (x)= ( x + 1 )/2

b) f^(-1) (x)= ( - x + 1 )/2

c) f^(-1) (x)= ( - x - 1 )/2

d) f^(-1) (x)= ( x - 1 )/2

e) n.d

​

Answer 1

façamos f(x)=y

$\mathsf{y=2x+1}\\\mathsf{2x=y-1}\\\mathsf{x=\dfrac{y-1}{2}}\\\implies\large\boxed{\boxed{\boxed{\boxed{\mathsf{f^{-1}(x)=\dfrac{x-1}{2}}}}}}$

$\huge\boxed{\boxed{\boxed{\boxed{\mathsf{\maltese~~alternativa~~d}}}}}$