Question

J=80;i=2%=0,02 e C =800.
C=80=800.0,02.t
80=20.t>t=80 >t=
20

Answer 1

Resposta:

Explicação passo a passo:

$J=80$

$i=0,02$

$C=800$

$t=?$

$J=C\:.\:i\;.\:t$

$80=800\:.\:(0,02)\:.\:t$

$\frac{80}{80}=\frac{800}{80}\:.\:(0,02)\:.\;t$

$1=10\:.\:(0,02)\:.\:t$

$0,2t=1$

$t=1/0,2$

$t=5$