Question

j) (3x-2)^2= (2-x)^2

Answer 1

Resposta:

(3x - 2)² = (2 - x)²

9x² - 12x + 4 = 4 - 4x + x²

9x² - x² - 12x + 4x + 4 - 4 = 0

8x² - 8x = 0

a = 8

b = -8

c = 0

Δ = b² - 4ac

Δ = (-8)² - 4 * 8 * 0

Δ = 64 - 0

Δ = 64

x' = -b ± √Δ / 2a

x' = -(-8) ± √64 / 2 * 8

x' = 8 + 8 / 16

x' = 16/16

x' = 1

x" = 8 - 8 / 16

x" = 0/16

x" = 0

Explicação passo-a-passo: