Question

interpole três meios geométricos entre 5 e 1280 resposta:​

Answer 1

Resposta:q= ± 4

Explicação passo-a-passo:

K=3-->n=K+2-->n=3+2--->n=5 termos,a1=5,a5=1280,q=?

an=a1.q^n-1

1280=5.q^5-1

1280=5.q^4

q^4=1280/5

q^4=256

q= ± 4^√256

q=± 4^√4^4

q= ± 4

PG(5,20,80,320,1280)

PG(5,-20,80,-320,1280)