Question

interpole sete meios geometricos entre 5 e 32805

Answer 1

P.G.(5,          32 805)
n = 9
a 9 = 32805
a 9 = a 1 . q^n - 1
a 9 = 5 . q^9-1
a 9 = 5 . q^8
32805 = 5 . q^8
32805 / 5 = q^8
6561 = q^8
3^8 = q~8
q = 3
a 2 = a 1 .q^2 - 1
a 2 = 5 . 3^1
a 2 = 15
a 3 = a 2 . 3 = 15 . 3 =45
a 4 = a 3 . 3 = 45 . 3 = 135
a 5 = a 4 . 3 = 135 . 3 = 405
a 6 = 405 . 3 = 1215
a 7 = 1215 . 3 = 3645
a 8 = 3645 . 3 = 10935
a 9 = 10935 . 3 = 32805

P.G.(5,15,45,135,405,1215,3645,10935,32805)