Question

Interpole quatro meios aritiméticos entre -12 e 48.
ME AJUDEM!

Answer 1

a1 = -12
an = 48
n = 6
r=?

an = a1 + (n-1) r
48 = -12 + (6 -1) r
48 = -12 + 5r
48+12 = 5r
60 = 5r
r = 60 / 5
r = 12

{-12; 0; 12; 24; 36; 48} -----> resposta

Answer 2

$a_n=48 \\ a_1=-12 \\ r=? \\ n=4+2=6 \\ \\ termo ~~geral \\ a_n=a_1+(n-1)r \\ \\ 48=-12+(6-1)r \\ 48+12=5r \\ 5r=60 \\ r=60\div5 \\ r=12$

se r = 12

$a_1=-12 \\ a_2=-12+12=0 \\ a_3=0+12=12 \\ a_4=12+12=24 \\ a_5=24+12=36 \\ a_6=36+12=48 \\ \\ P.A=(-12,0,12,24,36,48) \\ \\ os~~termos~~entre~~s\tilde{a}o~~(0,12,24,36)$