Question

Interpole dois meios geométricos entre 5 e 40.

Answer 1

resposta

a1=5

a1=5 an=40

a1=5 an=40n= 2+2

a1=5 an=40n= 2+2 n=4

a1=5 an=40n= 2+2 n=4 an= a1.q^n-1

a1=5 an=40n= 2+2 n=4 an= a1.q^n-140=5.q^-1

a1=5 an=40n= 2+2 n=4 an= a1.q^n-140=5.q^-140/5= q^3

a1=5 an=40n= 2+2 n=4 an= a1.q^n-140=5.q^-140/5= q^3 q^3=8

a1=5 an=40n= 2+2 n=4 an= a1.q^n-140=5.q^-140/5= q^3 q^3=8 q=³√8

a1=5 an=40n= 2+2 n=4 an= a1.q^n-140=5.q^-140/5= q^3 q^3=8 q=³√8 q=2