Question

interpole cinco meios aritmeticos entre -2 e 40

Answer 1

P.A.(-2,5,12,19,26,33,40)
A 1  = -2
A 7 = 40
N = 7
A 7 = A 1 + (N - 1 ) .R
40 = -2 + (7 - 1 ).R
40 = - 2 + 6 . R
40 + 2 = 6 R
42 = 6 R
42/6 = R
R = 7
A 2 = A1 + (N - 1 ).7
A 2 = -2 + (2-1).7
A 2 = -2 + 1 . 7
A 2 = -2 + 7⇒ + 5
A 3 = 5 +7 ⇒12
A 4 = 12 + 7 = 19
A 5 = 19 + 7  = 26
A 6 = 26 + 7 = 33
A 7 = 33 + 7 = 40