Question

Interpole 8 meios aritméticos entre 62 e 125

Answer 1

1° vamos calcular a razão:

$a_1=62\\a_n=125\\n=10\\r=?\\\\ a_n=a_1+(n-1)*r\\\\ 125=62+(10-1)*r\to \\\\ 125=62+10r-r\to \\\\ 125-62=+9r\to \\\\ 63=9r\to \\\\ \frac{63}{7} =r\to \\\\ r=7$


Encontrando os termos a partir da razão = 7

$a_1=62\\\\ a_2=a_1+r\to a_2=62+7\to a_2=69\\\\ a_3=a_2+r\to a_3=69+7\to a_3=76\\\\ a_4=a_3+7\to a_4=76+7\to a_4=83\\ \\ a_5=a_4+7\to a_5=83+7\to a_5=90\\\\ a_6= a_5+7\to a_6=90+7\to a_6=97\\\\ a_7=a_6=+7\to a_7=97+7\to a_7= 104\\\\a_8=a_7+7\to a_8=104+7\to a_8=111\\\\ a_9= a_8+7\to 111+7\to a_9=118\\\\ a_10=a_9+7\to a_10=118+7\to a_10=125$

Interpolando esses meios aritméticos:

R.: PA={62, 69, 76, 83, 90, 97, 104, 111, 118, 125}



Espero ter ajudado, bons estudos...