Question

Interpole 6 meios aritméticos entre 5 e 33

Answer 1

an=a1+(n-1)r, sendo an=ultimo termo, a1=primeiro termo, n= numero de termos, r= razão

33=5+(8-1)r
7r=33-5
r=28/7
r=4

Meios={5, 9, 13, 17, 21, 25, 29, 33}

Bons Estudos!!

Answer 2

Interpole 6 meios aritméticos entre 5 e 33

5,___,___,___,___,___,___33

An = A1 + (N - 1)*R
33 = 5 + (8 - 1)*R
33 = 5 + 7R
7R + 5 = 33
7R = 33 - 5
7R = 28
R = 28/7
R = 4

PA = ( 5,9,13,17,21,25,29,33)


RESPOSTA : R = 4