Question

interpole 5 meios aritméticos entre 4 e 22

Answer 1

a1 = 4
an = 22
n = 7
r = ?

an = a1 + (n-1).r
a7 = a1 + (7-1).r
22 = 4 + 6r
6r = 22 -4
6r = 18
r = 18/6
r = 3

P.A (4, 7, 10, 13, 16, 19, 22)

Answer 2

an = a₁ + (n-1) r             a₁ =4       an=22   n = 7

22 = 4 + (7-1) r

22 = 4 + 6r

22 - 4 = 6r

18 = 6r  

r = 3

{4-7-10-13-16-19-22}