Question

interpole 5 meio aritmético entre 6 e 30

Answer 1

Olá!

(6,...,...,...,...,...,30)
an=30
n=7
a1=6
r=?

an=a1+(n-1)×r
a7=6+(7-1)×r
30=6+6×r
30=6+6r
30-6=6r
24=6r
r=24÷6
r=4

(6,10,14,18,22,26,30)

Answer 2

P.A.(6,a 2 , a 3 , a 4 , a 5 , a 6 , 30)
a 1 = 6
a 7 = 30
a 7 = a 1 + (n - 1 ).r
a 7 = 6 + (7 - 1 ).r
a 7 = 6 + 6 . r
30 = 6 + 6 .r
30 - 6 = 6 r
24 = 6 r
24 / 6 = r
r = 4
a 2 = a 1 + r
a 2 = 6 + 4 = 10
a 3 = a 2 + r
a 3 = 10 + 4 = 14
a 4 = a 3 + r
a 4 = 14 + 4 = 18
a 5 = a 4 + r
a 5 = 18 + 4 = 22
a 6 = a 5 + r
a 6 = 22 + 4 = 26
a 7 = a 6 + r
a 7 = 26 + 4 = 30
P.A.(6,10,14,18,22,26,30)