Question

interplore 12 meios aritméticos entre 12 e 155, de modo que dormem uma p.a
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Answer 1

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$\sf(12,\underline{},\underline{},\underline{},\underline{},\underline{},\underline{},\underline{},\underline{},\underline{},\underline{},\underline{},\underline{},155)\\\sf a_1=12~~a_{14}=155\\\sf a_{14}=a_1+13r\\\sf 155=12+13r\\\sf 13r=155-12\\\sf13r=143\\\sf r=\dfrac{143}{13}\\\sf r=11$

$\sf(12,\underline{23},\underline{34},\underline{45},\underline{56},\underline{67},\underline{78},\underline{89},\underline{100},\underline{111},\underline{122}.\underline{133},\underline{144},155)$