Question

Integral indefinida (URGENTE)
a) ∫cos5xdx fazer 5x=t
b) ∫senxcos^7xdx fazer cosx=t

Answer 1

a)
∫cos5x dx

t=5x,
dt=5 dx
dx=dt/5

∫cos t dt/5
(1/5)∫cost dt

(1/5)*sen t=
(sen5x)/5 +C

b)∫senxcos⁷x dx
t=cosx
dt=-senx dx

∫ t⁷ dt=
t⁸/8=
-(cos⁸x)/8 +C