Question

Integral de 1 a 3 (2× ao quadrado +2×)dx

Answer 1

$\int\limits^3_1 {x^{2}+2x \, dx = [\frac{x^3}{3}+2\frac{x^2}{2}] ^3_1 = (\frac{3^3}{3}+3^2.}{2}) - (\frac{1^3}{3}+1) = 9+18-\frac{1}{3} -1 =\frac{77}{3}= 25,667$