Question

Int(9t^2+1/vt^3)dt integral e derivada

Answer 1

Resposta:

a)

∫ (9t²+1/v*t³)  dt

=∫ 9t²  dt   +  (1/v) ∫ 1/t³  dt

= 9 *t³/3  +(1/v) * ∫ t⁻³  dt

= 9 *t³/3  +(1/v) *  t⁻²/(-2) + constante

=3t³-(1/2v) * t⁻² + constante

=3t³- 1/(2t²v) + constante

b)

d (3t³- 1/(2t²v) + constante)/dt =   (9t²+1/v*t³)