Question

Insira quatro meios geometricos entre 6 e 192

Answer 1

$a_6=a_1.q^5 \\ \\ 6.q^5=192 \\ \\ q^5=\frac{192}{6} \\ \\ q^5=32 \\ \\ q=2$

Logo a PG será:  PG(6,12,24,48,96, 192)

Answer 2

$P.G(6,...,...,...,...,192)$

$a_n = a_1 *q^{n-1}$

$192 = 6 *q^{n-1}$

$q^{n-1} = 32$

$q^{6-1} = 32$

$q^{5} = 32$

$\boxed{q=2}$

$P.G(6,12,24,48,96,192)$

Lembrando que:

$a_n = a_6 = 192$

Espero ter ajudado. :))