Question

insira dez meios aritméticos entre 1/5 e 166/5

Answer 1

P.A.(1/5,       166/5)
A 12 = 166/5
A 12 = A 1 + (N - 1)
A 12 = 1/5 + (12 - 1 ).R
166/5 - 1/5 = 11 R
165/5 = 11 R
33 = 11 R
11 R = 33
R = 33/11
R = 3
A 1 = 1/5
A 2 = A 1 + 3
A 2 + 1/5 + 3⇒1/5 + 15/5 = 16/5
A 3 = A 2 + 3⇒16/5 + 3 = 16/5 + 15/5 = 31/5
A 4 = A 3 + 3 = 31/5 + 3 = 31/5 + 15/5 = 46/5
A 5 = A 4 + 5 ⇒46/5 + 3 = 46/5 + 15/5 = 61/5
A 6 = A 5 + 3 ⇒61/5 + 3 = 61/5 + 15/5 = 76/5
A 7 = A 6 + 3⇒76/5 + 3 = 76/5 + 15/5 = 91/5
A 8 = A 7 + 3 ⇒91/5 + 3 = 91/5 + 15/5 = 106/5
A 9 = A 8 + 3 ⇒ 106/5 + 3 = 106/5 + 15/5 = 121/5
A 10 = A 9 + 3⇒121/5 + 3 = 121/5 + 15/5 = 136/5
A 11 = A 10 + 3 ⇒ 136/5 + 15/5 = 151/5
A 12 = A 11 + 3 ⇒151/5 + 3 = 151/5 + 15/5 = 166/5