Question

Insira 5 meios aritméticos entre 4 e 256

Answer 1

a 1 = 4
a 7 = 256
n = 7
a 7 = a 1 + (n - 1).r
a 7 = 4 + (7 - 1 ).r
a 7 = 4 + 6 r
256 = 4 + 6 r
256 - 4 = 6 r
256 - 4 = 6 r
252 = 6 r
252 / 6 = r
r = 42
a 2 = a 1 + r ⇒ 4 + 42 = 46
a 3 = a 2 + r ⇒ 46 + 42 =88
a 4 = a 3 + r ⇒88 + 42 = 130
a 5 = a 4 + r ⇒ 130 + 42 = 172
a 6 = a 5 + r ⇒ 172 + 42 = 214
a 7 = a 6 + r ⇒214 + 42 = 256

P.A.(4;46;88;130;172;214;256 )