Question

Inserir 7 meios aritméticos entre 19/3 e 7/3​

Answer 1

$(\underline{a_{1},a_{2},a_{3},a_{4},a_{5},a_{6},a_{7},a_{8},a_{9}})$

$a_{1}=\dfrac{19}{3}$

$a_{9}=\dfrac{7}{3}$

$a_{9}=a_{1}+8r\\\dfrac{7}{3}=\dfrac{19}{3}+8r\times(3)$

$7=19+24r\\24r=7-19\\24r=-12\\r=-\dfrac{12}{24}$

$\bf{r=-\dfrac{1}{2}}$

$(\underline{\dfrac{19}{3},\dfrac{35}{6},\dfrac{16}{3},\dfrac{29}{6},\dfrac{13}{3},\dfrac{23}{6},\dfrac{10}{3},\dfrac{17}{6},\dfrac{7}{3}})$