Question

inequação expónencial

(√2)^× ≤$\frac{1}{16}$

(√2)^× ≤$\frac{1}{16}$

Answer 1

$(\sqrt{2})^{x}\le\dfrac{1}{16}$

$\left(2^{\frac{1}{2}}\right)^{x}\le\dfrac{1}{2^4}$

$2^{\frac{x}{2}}\le2^{-4}$

$\dfrac{x}{2}\le-4$

$x\le-8$

$S=\{x\in\mathbb{R}~|~x\le-8\}$.