Question

INEQUAÇÃO EM IR:
2x²+x-1>0

Answer 1

$2 x^{2} +x-1\ \textgreater \ 0$

Δ=b²-4.a.c
Δ=(1)²-4.(2).(-1)
Δ=1+8
Δ=9

x=(-b)+-√Δ ÷ 2.a
x=-1+- (3) ÷ 4

x1= -1+3 ÷ 4
x1= 2 ÷ 4
x1= 1/2

x2=-1-3 ÷ 4
x2= -4 ÷ 4
x2= -1

S= {XE|R/ -1 > x > 1/2}