Question

Indique os zeros das seguintes funções: Y=x2-7x+10. Y=2x2-3x+4. F(x) 3x2-7x+2
Y=4-x2. F(x)=x2+2×+1

Answer 1

y=x^2-7x+10
x^2-7x+10=0
delta=b^2-4.a.c
delta=(-7)^2-4.1.10
delta=49-40
delta=9
x=-b-/+ raiz de delta/2a
x=-(-7)-3/2.1
x=7-3/2
x=4/2
x=2
x=-(-7)+3/2.1
x=7+3/2
x=10/2
x=5
y=2x^2-3x+4
2x^2-3x+4=0
delta=b^2-4.a.c
delta=(-3)^2-4.2.4
delta=9-32
delta=-23
delta negativo, não há raízes reais.
3x^2-7x+2=0
delta=b^2-4.a.c
delta=(-7)^2-4.3.2
delta=49-24
delta=25
x=-b-/+ raiz de delta/2a
x=-(-7)-5/2.3
x=7-5/6
x=2/6 (:2)
x=1/3
x=-(-7)+5/2.3
x=7+5/6
x=12/6
x=2
y=4-x^2
4-x^2=0
-x^2+4=0
delta=b^2-4.a.c
delta=0^2-4.(-1).4
delta=0+16
delta=16
x=-b-/+ raiz de delta / 2a
x=-0-4/2. (-1)
x=-4/-2
x=2
x=-0+4/2.(-1)
x=4/-2
x=-2
f(x)=x^2+2x+1
x^2+2x+1=0
delta=b^2- 4.a.c
delta=2^2-4.1.1
delta=4-4
delta=0
x=-b-/+ raiz de delta/2a
x=-2-0/2.1
x=-2/2
x=-1