Question

indique o numero de protons eletrons e neutros de z= 26 e A= 56

Answer 1

$\boxed{\boxed{z=n^op^+=n^oe^-=26}}$

$A=n^op^++n^on^0$

$n^on^0=A-n^op^+$

$n^on^0=56-26$

$\boxed{\boxed{n^on^0=30}}$