Question

Indique a forma algébrica e seu conjugado do número complexo z=[10.(cos3π\2+ i.sen3π/2)]

Answer 1

z= 10.(cos3π\2+ i.sen3π/2)

z=10. (cos270° + i.sen270)

z=10.( 0 + i. -1)

z= 10.(0 - i)

z= 10.(-i)

z = -10i (forma algébrica)

z'=10i (conjugado)

Answer 2

$a=10.\cos(\dfrac{3\pi}{2}) =10.0=0$

$b=10.\sin(\dfrac{3\pi}{2}) =10.(-1)=-10$

$\mathsf{Z=a+bi} \\\boxed{\boxed{\mathsf{Z=-10i}}}$ →forma algébrica

$\boxed{\boxed{\mathsf{\overline{Z}=10i}}}$→conjugado