Question

II – RESOLVA AS INEQUAÇÕES A SEGUIR:

6°) 2x + 2 > 0

7°) 2x + 6 ≥ 2

8°) x + 3 < 2

9°) 2x + 2 ≤ x + 1

10°) 6x + 5 ≤ x + 15​

Answer 1

6) 2x + 2 > 0

   2x > -2

   x > -1

7) 2x + 6 ≥ 2

   2x ≥ -4

   x ≥ -2

 

8) x + 3 < 2

   x < -1

9) 2x + 2 ≤ x + 1

   2x - x ≤ 1 - 2

   x ≤ -1

10) 6x + 5 ≤ x + 15

     6x - x ≤  15 - 5

     5x ≤ 10

     x ≤ 2

Answer 2

$\large{a)2x + 2 > 0}$

$\large{2x > 0 - 2}$

$\large{2x > - 2}$

$\large{x > - 2 \div 2}$

$\large \boxed{ \red{{x > - 1}}}$

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$\large{b)2x + 6 \geqslant 2}$

$\large{2x \geqslant 2 - 6}$

$\large{2x \geqslant - 4}$

$\large{x \geqslant - 4 \div 2}$

$\large \boxed{ \red{{x \geqslant - 2}}}$

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$\large{c)x + 3 < 2}$

$\large{x < 2 - 3}$

$\large \boxed{ \red{{x < - 1}}}$

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$\large{d)2x + 2 \leqslant x + 1}$

$\large{2x - x \leqslant 1 - 2}$

$\large \boxed { \red{x \leqslant - 1}}$

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$\large{e)6x + 5 \leqslant x + 15}$

$\large{6x - x \leqslant 15 - 5}$

$\large{5x \leqslant 10}$

$\large{x \leqslant 10 \div 5}$

$\large \boxed{ \red{x \leqslant 2}}$

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Att, IzabelaCristina2006 ❤️ ♈