Question

iguale e resolva utilizando o método bhaskara: 4-5x ² =2x

Answer 1

Ola!!

Têm-se:

$4-5x^2=2x$

${\color{blue}{-5x^2-2x+4=0}}$

Onde:

a=-5 ; b=-2 e c = 4

∆=(—2)²—4*(—5)*4

∆=4+80

∆=84

$\large\boxed{\boxed{{x_{1,2}=\frac{-b\pm\sqrt{\Delta}}{2*a}}}}}}$

$x_{1,2}=\frac{+2\pm\sqrt{84}}{2*(-5)}$

$x_{1,2}=\frac{2\pm\sqrt{84}}{-10}$

Dúvidas??Comente!!