Matemática, perguntado por joyce562, 1 ano atrás

i)3(2x-1)=-2(x+3) j)5x-3(x+2)=15 k)2x+3x+9=8(6-x) l)4(x+10)-2(x-5)=0 m)3(2x+3)-4(x-1)=3 n)7(x-1)-2(x-5)=x-5 o)2(3-x)=3(x-4)+15 p)3(5-x)-3(1-2x)=42 q)(4x+6)-2x=(x-6)+10+14 r)(x-3)-(x+2)+2(x-1)-5=0<br />S)3x-2(4x-3)=2-3(x-1)T)3(x-1)-(x-3)+5(x-2=18 u)5(x-3)-4(x+2)=2+3(1-2x)

Soluções para a tarefa

Respondido por Irysbm14
24
i)3(2x-1)=-2(x+3)
6x-3= -2x-6
6x+2x= -6+3
8x= -3
x= -3/8

j)5x-3(x+2)=15
5x-3x-6=15
2x= 15+6
2x= 21
x= 21/2

k)2x+3x+9=8(6-x)
5x+9=48-8x
5x+8x= 48-9
13x= 39
x= 39/13
x= 3

l)4(x+10)-2(x-5)=0
4x+40-2x+10=0
4x-2x+40+10= 0
2x+50=0
2x= -50
x= -50/2
x= -25

m)3(2x+3)-4(x-1)=3
6x+9-4x+4=3
6x-4x+9+4=3
2x+13=3
2x= 3-13
2x= -10
x= -10/2
x= -5

n)7(x-1)-2(x-5)=x-5
7x-7-2x+10= x-5
7x-2x+10-7=x-5
5x+3=x-5
5x-x= -5-3
4x= -8
x= -8/4
x= -2

o)2(3-x)=3(x-4)+15
6-2x= 3x-12+15
6-2x= 3x+3
6-3= 3x-2x
3= x
x= 3

p)3(5-x)-3(1-2x)=42
15-3x-3+6x=42
15-3+6x-3x=42
3x+12=42
3x= 42-12
3x= 32
x= 32/3

q)(4x+6)-2x=(x-6)+10+14
-4x-6+2x= x-6+10+14
-4x+2x-6= x-6+24
-2x-6= x+18
-6-18= x+2x
-24= 3x
3x= -24
x= -24/3
x= -8


r)(x-3)-(x+2)+2(x-1)-5=0
x-3-x-2+2x-2-5=0
-5+2x-7=0
2x-12=0
2x= 12
x= 12/2
x= 6

S)3x-2(4x-3)=2-3(x-1)
3x-8x+6=2-3x+3
-5x+6=5-3x
6-5= -3x+5x
1= 2x
2x= 1
x= 1/2

T)3(x-1)-(x-3)+5(x-2)=18
3x-3-x+3+5x-10=18
3x-x-3+3+5x-10=18
2x+5x= 18+10
7x= 28
x= 28/7
x= 4

u)5(x-3)-4(x+2)=2+3(1-2x)
5x-15-4x-8= 2+3-6x
5x-4x-15-8= 5-6x
x-23= 5-6x
x+6x= 5+23
7x= 28
x= 28/7
x= 4
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