Question

I) 2 (5y+1) =27. J) 6(x+3)-2(x-5)=20

Answer 1

Olá,

Vamos lá,

I) 2 (5y+1) =27
10y + 2 = 27
10y = 27 -2
10y = 25
y = 25/10
y = 2,5

J) 6(x+3)-2(x-5)=20
6x + 18 -2x +10 = 20
6x -2x = 20 - 18 - 10
2x = -8
x = -8/2
x = - 4

Answer 2

 l) 2(5y+1)=27
 2.5y=10y+2.1=2=27
 10y=27-2
 10y=25
  y=25/10
  y=2,5


J) 6(x+3)-2(x-5)=20 
6x + 18 -2x +10 = 20
6x -2x = 20 - 18 - 10
2x = -8
x = -8/2
x = - 4