Question

HELPP
(Mackenzie-SP)
CH4(g) + 2 O2(g) - CO2(g) + 2 H2O(g)
O volume de CO2 produzido na combustão de 960,0 g de metano, é:
massa molar do CH4 = 16,0 g/mol

A-1344 litros
B-60 litros
C-30 litros
D-100 litros
E-40 litros​

Answer 1

$\mathsf{CH_{4}} +2O_{2} \rightarrow~CO_{2} +2H_{2}O$

$\mathsf{16\,g\,de\,CH_{4}\to\,22,4L\,de\,CO_{2}}\\\mathsf{960g\,de\,CH_{4}\to\,x}$

$\mathsf{16x=960.22,4}\\\mathsf{x=\dfrac{960.22,4}{16}}\\\mathsf{x=60.22,4}$

$\boxed{\boxed{\boxed{\mathsf{x=1344~L}}}}$