Question

Help na calcula!!
a) (16a4-4a3+12a2):(-4a)
b) (49x4-14x3-35x2):(7x2)
“OBRIGADA" (:

Answer 1

$a) \frac{16a^4-4a^3+12a^2}{-4a} = \\ \\ = \frac{4a^2(4a^2-a+3)}{-4a} = \\ \\ =-a(4a^2-a+3a)=-4a^3+a^2-3a^2 \\ \\ \\ b) \frac{49x^4-14x^3-35x^2}{7x^2} = \\ \\ = \frac{7x^2(7x^2-2x-5)}{7x^2} =7x^2-2x-5$