Question

h)3.(x-1)=6

i)2.(x+15)=-4

j)3.(2y-5)=9

Answer 1

Resposta:

$3 \times (x - 1) = 6 \\ 3x - 3 - 6 = 0 \\ 3x - 9 = 0 \\ 3x = 9 \div (3) \\ x = 3$

$2 \times (x + 15) = - 4 \\ 2x + 30 = - 4 \\ 2x + 30 + 4 = 0 \\ 2x +34 = 0 \\ 2x = - 34 \div (2) \\ x = - 17$

$3 \times (2y - 5) = 9 \\ 6y - 15 = 9 \\ 6y - 15 - 9 = 0 \\ 6y - 24 = 0 \\ 6y = 24 \div (6) \\ y = 4$