Gostaria de saber como resolver isso (raiz quarta, mas não sei colocar o numero no índice): 4√(2^29+2^31)/10
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![\frac{ \sqrt[4]{ {2}^{29} + {2}^{31} } }{10} = \\ \\ \frac{ \sqrt[4]{ {2}^{60} } }{10} = \\ \\ \frac{ {2}^{ \frac{60}{4} } }{10} = \\ \\ \frac{ {2}^{15} }{10} = \\ \\ \frac{32768}{10} = \\ \\ 3276.8](https://tex.z-dn.net/?f=+%5Cfrac%7B+%5Csqrt%5B4%5D%7B+%7B2%7D%5E%7B29%7D+%2B++%7B2%7D%5E%7B31%7D++%7D+%7D%7B10%7D++%3D+%5C%5C++%5C%5C++%5Cfrac%7B+%5Csqrt%5B4%5D%7B+%7B2%7D%5E%7B60%7D+%7D+%7D%7B10%7D++%3D++%5C%5C++%5C%5C++%5Cfrac%7B+%7B2%7D%5E%7B+%5Cfrac%7B60%7D%7B4%7D+%7D+%7D%7B10%7D++%3D++%5C%5C++%5C%5C++%5Cfrac%7B+%7B2%7D%5E%7B15%7D+%7D%7B10%7D++%3D++%5C%5C++%5C%5C++%5Cfrac%7B32768%7D%7B10%7D++%3D++%5C%5C++%5C%5C+3276.8 "\frac{ \sqrt[4]{ {2}^{29} + {2}^{31} } }{10} = \\ \\ \frac{ \sqrt[4]{ {2}^{60} } }{10} = \\ \\ \frac{ {2}^{ \frac{60}{4} } }{10} = \\ \\ \frac{ {2}^{15} }{10} = \\ \\ \frac{32768}{10} = \\ \\ 3276.8")
Respondido por
1
4\|(2^29 + 2^31)
____________
.............10
4\|2^60
..............
----10
2^60/4
______
----10
2^5
___
.10
32768
_____
....10
3276,80
____________
.............10
4\|2^60
..............
----10
2^60/4
______
----10
2^5
___
.10
32768
_____
....10
3276,80
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