Question

gnt me ajudem e para calcular

Answer 1

√{ 1/2[1/(√x/y)] - 1/2[1/√(y/x)]^-2 + 1}
√{[1/2×(√y/√x)  - 1/2(√x/√y)].^-2  + 1}
m.m.c ⇒ 2√x√y
√{[(y - x )]/(2√x√y)]^-2 + 1}

√ {1/[( y - x)²/4xy] + 1}
√ [4xy/(y - x)² + 1]
√[4xy + y² -2xy + x²]/(y - x)²
√(x² + 2xy + y²)/(x² - 2xy + y²)
√ (x + y)²/(x - y)²
(x + y)/(x - y)