Given that 2x+3y/3x+4y=5 find the ratio y:x
Soluções para a tarefa
Reply:
x= 5-4y/2+4y,y≠-2
Step by step explanation:
2x+3xy/3xx+4=5
Multiply both sides (if you don't know how to do this, I'll explain it to you now!)
Multiply company members by 3
3(2x+3xy/3xx+4y)=3x5
Use the distributive property of multiplication and multiply each term inside the parentheses by 3
3x2x+3x3xy/3xx+3x4y=3x5
multiply the values
3x2x+3x3xy/3xx+3x4y=15
calculate a multiplication
6x+3x3xy/3xx+3x4y=15
Simplify numbers by dividing them by the greatest common factor 3
6x+3xy+3x4y=15
calculate a multiplication
62xy+1y=15 and that we multiply the members of the family x like this by 3)
6x+3yx+12y=15
Put the factor x in evidence in the expression
(6+3y)x+12y=15
Move the variables to the right member and change its sign (if not explain) this, I will explain it to you
Move the variable to the right member by adding or its opposite to both members
(6+3y)x+12y-12y=15-12y
Since the sum of two opposites is zero, removing them from the expression
(6+3y)x=15-12y (and this is how we move like variables to the right member and change the signs)
(6+3y)x=15-12y
Assume 6+3y≠0 and divide both query members by assume 6+3y
x=15-12y/6+3y,6+3y≠0
rewrite the constraint
x=15-12y/6+3y,y≠-2
Put the factor 3 in evidence in the expression
x=3(5-4y)/6+3y,y≠-2
x=3(5-4y)/3(2+y),y≠-2
Reduce the offer with 3
x=5-4y/2+y,y≠-2
and there we have the solution, hope it helped :>