Question

Geometria Analitica. Segue questão em anexo

Answer 1

Resposta:

b.9✅

Explicação passo-a-passo:

espero ter ajudado

Answer 2

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\begin{cases}\mathsf{x + y + x = 1}\\\mathsf{x + y - z = -3}\\\mathsf{x - y + z = 3}\end{cases}$

$\mathsf{\begin{bmatrix}\cancel1&\cancel1&\cancel1\\\cancel1&\cancel1&\cancel-1\\\cancel1&\cancel-1&\cancel1\end{bmatrix}}$

$\mathsf{D = (1 - 1 - 1) - (1 + 1 + 1)}$

$\mathsf{D = (-1) - (3)}$

$\mathsf{D = -4}$

$\mathsf{\begin{bmatrix}\cancel1&\cancel1&\cancel1\\\cancel-3&\cancel1&\cancel-1\\\cancel3&\cancel-1&\cancel1\end{bmatrix}}$

$\mathsf{D_X = (1 - 3 + 3) - (3 + 1 - 3)}$

$\mathsf{D_X = (1) - (1)}$

$\mathsf{D_X = 0}$

$\mathsf{\begin{bmatrix}\cancel1&\cancel1&\cancel1\\\cancel1&\cancel-3&\cancel-1\\\cancel1&\cancel3&\cancel1\end{bmatrix}}$

$\mathsf{D_Y = (-3 - 1 + 3) - (-3 - 3 + 1)}$

$\mathsf{D_Y = (-1) - (-5)}$

$\mathsf{D_Y = (-1) + (5)}$

$\mathsf{D_Y = 4}$

$\mathsf{\begin{bmatrix}\cancel1&\cancel1&\cancel1\\\cancel1&\cancel1&\cancel-3\\\cancel1&\cancel-1&\cancel3\end{bmatrix}}$

$\mathsf{D_Z = (3 - 3 - 1) - (1 + 3 + 3)}$

$\mathsf{D_Z = (-1) - (7)}$

$\mathsf{D_Z = -8}$

$\mathsf{x = \dfrac{D_X}{D} = \dfrac{0}{-4} = 0}$

$\mathsf{y = \dfrac{D_Y}{D} = \dfrac{4}{-4} = -1}$

$\mathsf{z = \dfrac{D_Z}{D} = \dfrac{-8}{-4} = 2}$

$\mathsf{x^2 + y^2 + 2z^2 = 0^2 + (-1)^2 + 2.(2)^2}$

$\mathsf{x^2 + y^2 + 2z^2 = 0 + 1 + 2.(4)}$

$\mathsf{x^2 + y^2 + 2z^2 = 0 + 1 + 8}$

$\boxed{\boxed{\mathsf{x^2 + y^2 + 2z^2 = 9}}}\leftarrow\textsf{letra B}$