Question

GENTEEEEEM
20 PONTOS

se f(x) = x/ x-2 e g(x)= 3/x ENTÃO( fog)(x) =

Answer 1

$f\left(x \right)=\dfrac{x}{x-2}\\ \\ g\left(x \right )=\dfrac{3}{x}\\ \\ \\ \left(f \circ g \right )\left(x \right )=f\left(g\left(x \right ) \right )\\ \\ \left(f \circ g \right )\left(x \right )=\dfrac{g\left(x \right )}{g\left(x \right )-2}\\ \\ \left(f \circ g \right )\left(x \right )=\dfrac{\frac{3}{x}}{\frac{3}{x}-2}\\ \\ \left(f \circ g \right )\left(x \right )=\dfrac{x\cdot \frac{3}{x}}{x\cdot \left(\frac{3}{x}-2 \right )}\\ \\ \left(f \circ g \right )\left(x \right )=\dfrac{3}{3-2x}$