Question

genteee socorro pra agora me ajudem com essas duas equacoes. x²+6x-8=0

-x²+5x-6=0

dou 31 pontooos , rapidoooooo gntt.

Answer 1

$x = \dfrac{-b \pm \sqrt{b^2 -4*a*c}}{2*a}$

$x^2 +6x - 8 = 0$

a=1, b=6, c=−8

Δ=b2−4ac
Δ=(6)2−4*(1)*(−8)
Δ=36+32
Δ=68

$x = \dfrac{-b \pm \sqrt{\triangle}}{2*a} \\ \\ \\ x = \dfrac{-6 \pm \sqrt{68}}{2*1} \\ \\ \\ x = \dfrac{-6 \pm 2\sqrt{17}}{2} \\ \\ \\ x' = \dfrac{-6 + 2\sqrt{17}}{2} \\ \\ x' = -3 + 2\sqrt{17} \\ \\ \\ x'' = \dfrac{-6 -\sqrt{17}}{2} \\ \\ x'' = -3 -\sqrt{17}$

S = {$-3 + \sqrt{17}, -3 - \sqrt{17}$}

==============================
$-x^2 + 5x -6 = 0$

a = -1,  b= 5,  c = -6

Δ=b2−4ac
Δ= 5^2−4*(-1)*(-6)
Δ=25−24
Δ=1$x = \dfrac{-b \pm \sqrt{\triangle}}{2*a} \\ \\ \\ x = \dfrac{-5 \pm \sqrt{1}}{2*-1} \\ \\ \\ x = \dfrac{-5 \pm 1}{-2} \\ \\ \\ x' = \dfrac{-5 + 1}{-2} \\ \\ \\ x' = \dfrac{-4}{-2} \\ \\ \\ x' = 2 \\ \\ x' = \dfrac{-5 - 1}{-2} \\ \\ x' = \dfrac{-6}{-2} \\ \\ \\ x' = 3$

S = {2, 3}