Question

gentee vcs podem me ajudar a resolver essa atividade é pra hj e não entendi muito bem vcs poderiam fazer

Answer 1

$c)\\ \\ 1+(\frac{10}{4} +\frac{2}{7} )-\frac{1}{2} \\ \\ mmc~parenteses=28\\ \\ 1+\frac{70+8}{28} -\frac{1}{2} =1+\frac{78}{28} -\frac{1}{2} \\ \\ mmc=28\\ \\ \frac{28+78-14}{28} =\frac{92}{28} =\frac{23}{7} </p> <p>[tex] d)\\ \\ (2-\frac{2}{3} )+(\frac{1}{5}- \frac{1}{6} )\\ \\ \frac{6-2}{3} +(\frac{1}{5} -\frac{1}{6} )=\frac{4}{3} +(\frac{1}{5} -\frac{1}{6} )\\ \\ mmc~parenteses=30\\ \\ \frac{4}{3}+(\frac{6-5}{30} )=\frac{4}{3} +\frac{1}{30} \\ \\ mmc=30\\ \\ \frac{40+1}{30} =\frac{41}{30}</p> <p>[tex] e)\\ \\ obs.:1\frac{1}{2} =\frac{1}{1} +\frac{1}{2} =\frac{2+1}{2}=\frac{3}{2} \\ \\ (\frac{1}{5} +\frac{2}{3} +\frac{3}{2} )-(\frac{1}{2} -\frac{1}{4} )\\ \\ mmc~1^{0} ~parenteses=30\\ \\ \frac{6+20+45}{30} -(\frac{1}{2} -\frac{1}{4} )=\frac{71}{30} -(\frac{1}{2} -\frac{1}{4} )\\ \\ mmc~2^{0} ~parenteses=4\\ \\ \frac{71}{30} -\frac{2-1}{4} =\frac{71}{30} -\frac{1}{4} \\ \\ mmc=60\\ \\ \frac{142-15}{60} =\frac{127}{4}$

$a)\\ \\ \frac{2}{3} +(\frac{4}{5} -\frac{1}{4} )=\frac{2}{3} +(\frac{16-5}{20} )=\frac{2}{3} +\frac{11}{20} =\frac{40+33}{60} =\frac{77}{60} \\ \\ b)\\ \\ 2+(\frac{2}{3} -\frac{1}{3} +\frac{5}{3} )=\frac{2}{1} +\frac{2-1+5}{3} =\frac{2}{1} +\frac{6}{3} =\frac{6+6}{3} =\frac{12}{3} =4$