Matemática, perguntado por clarahelena3, 1 ano atrás

Gente, um trab q n sei fazer, me ajudem!!!
a) (2x+3).(2x+5)
b) (4a²b+3).(4a²b-9)
c) (5x³+13).(5x³-11)
d) [m²+2/5a].[m²-1/3a]
e) (a+b+2).(a+b-3)

Soluções para a tarefa

Respondido por LuanaSC8
4
a)~~ (2x+3).(2x+5)\to~~ 4x^2+10x+6x+15\to~~ \large\boxed{4x^2+16x+15}\\\\\\\\\\b)~~ (4a^2b+3).(4a^2b-9)\to ~~ 16a^4b^2-36a^2b+12a^2b -27\to\\\\ \large\boxed{  16a^4b^2-24a^2b -27 }\\\\\\\\\\ c) ~~(5x^3+13).(5x^3-11)\to~~ 25x^6-55x^3+65x^3-143\to\\\\ \large\boxed{  25x^6+10x^3-143  }





d)~~ \left[m^2+ \dfrac{2a}{5} \right]. \left[m^2- \dfrac{1a}{3} \right]\to~~ m^4- \dfrac{a}{3}m^2+ \dfrac{2a}{5} m^2- \dfrac{2a^2}{15} \to\\\\\\ m^4-5am^2+6am^2- \dfrac{2a^2}{15}\to ~~\large\boxed{  m^4+am^2- \dfrac{2a^2}{15} }





e) ~~(a+b+2).(a+b-3)\to\\\\a^2+ab-3a+ab+b^2-3b+2a+2b-6\to \\\\a^2+b^2+ab+ab-3a+2a-3b+2b-6\to\\\\   \large\boxed{a^2+b^2+2ab-a-b-6}
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