Question

gente, respondam essa pfv.


Resolva as expressões:

a) $10^{2} : \sqrt{25} + 4^{0} - 5=$


b) $\sqrt{100} + 13^{2} - 10^{2} =$


c) ( 100 - 5 x 8 ) : ( 20 - 8 : 2 )


d) [ ( $3^{4} + 4 ) + 25] + 5 x ( 42 : 7 + 28 )=$

Answer 1

$a) {10}^{2} \div \sqrt{25} + {4}^{0} - 5 \\ 100 \: \div 5 + 1 - 5 = > \\ 20 + 1 - 5 = 16$

$b) \sqrt{100} + {13}^{2} - {10}^{2} \\ 10 + 169 - 100 = 79$

$c) \: (100 - 5 \times 8) \div (20 - 8 \div 2) \\ (100 - 40) \div (20 - 4) = > \\ 60 \div 16 = 3.75$

$d) | ({3}^{4} + 4) + 25| + 5 \times \\ (42 \div 7 + 28) \\ |(81 + 4) + 25| + 5 \times (6 + 28) = > \\ |85 + 25| + 5 \times 34 = >$

$110 + 170 = 280$

Espero ter ajudado!!!