Question

Gente por favor, me ajudem! Só falta essa .

Answer 1

Log √32 = log 2^5
log 512 = log 2^9
log 16 = log 2^4
log 5 = log 10/2 = log 10 - log 2

(log √32 + log 512)/(log 16 . log 10)
(1/2.log 2^5 + log 2^9)/(log 2^4 . (log 10 - log 2))
(1/2.5.log 2 + 9.log 2)/(4.log 2 . (log 10) - log 2))
(1/2.5.0,301 + 9.0,301)/(1,204. (1 - 0,301)
(0,7525 + 2,709)/(1,204 . (0,699))
(3,4615)/( 0,8415)
Resposta: 4,11
Espero ter ajudado

Answer 2

Ola Cristiane

log(√32) = log(2^5)/2 = 5*log(2)/2

log(512) = log(2^9) = 9log(2)

log(16= log(2^4) = 4*log(2)

log(5) = log(10/2) = 1 - log(2)

E = (5*log(2)/2 + 9log(2) )/(4*log(2) *(1 - log(2) )

E = 23*log(2)/(8log(2) - 8log(2)²)

E = 23/(8*(1 - log(2)) 

E = 23/(8*(1 - 0.30103))

E = 23/(8*0.69897)= 4.1132 

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