Question

gente por favor me ajudem

Answer 1

a) log 6 = log (3.2) = log 3 + log 2 = b+a
b) log 24 = log (2³.3) = log 2³ + log 3 = 3.log 2 + log 3 = 3a+b
c) log 300 = log (3.10²) = log 3 + log 10² = log 3 +2.log 10 = b+2
OBS: log 10 = 1
d) log 1,5 = log (3/2) = log 3 - log 2 = b-a
e) log 16 = log (2^(4)) = 4.log 2 = 4a
f) $log_{3} 2$ = $\frac{log 2}{log3} = \frac{a}{b}$