Question

gente plmds me ajudem!!!!
Resolva, em Q, a equação:

Answer 1

$2x - \frac{3x + 2}{4}+\frac{x}{3}-\frac{6(1-x)}{6} = \frac{x-2(x-1)}{2}$

$2x - \frac{3x + 2}{4}+\frac{x}{3}-\frac{6-6x)}{6} = \frac{x-2x+2}{2}$

$2x - \frac{3x + 2}{4}+\frac{x}{3}-\frac{6-6x)}{6} = \frac{2-x}{2}$

$Multiplique~ambos~os~lados~por~12~(MMC)$

$12(2x - \frac{3x + 2}{4}+\frac{x}{3}-\frac{6-6x)}{6}) = 12(\frac{2-x}{2})$

$12.2x-12.\frac{3x + 2}{4}+12.\frac{x}{3}-12.\frac{6-6x)}{6}) = 12.\frac{2-x}{2}$

$Simplifique~e~multiplique~cruzado$

$24x-3(3x+2)+4x-2(6-6x)=6(2-x)$

$24x-9x-6+4x-12+12x)=12-6x$

$31x -18=12-6x$

$37x=30$

$x = \frac{30}{37}$

$x = 0,810...$

$\rightarrow Att, Felipemlvr.$