Question

Gente mim ajudam por favor essa questão urgente ​

Answer 1

Explicação passo-a-passo:

a) A - B

   $\left[\begin{array}{ccc}1&5\\2&4\\-1&3\end{array}\right]-\left[\begin{array}{ccc}-2&-3\\1&0\\4&2\end{array}\right]$

   $\left[\begin{array}{ccc}1-(-2)&5-(-3)\\2-1&4-0\\-1-4&3-2\end{array}\right]$

   $\left[\begin{array}{ccc}1+2&5+3\\2-1&4-0\\-1-4&3-2\end{array}\right]=\left[\begin{array}{ccc}3&8\\1&4\\-5&1\end{array}\right]$

*****************************************************************************************

b) B - C

   $\left[\begin{array}{ccc}-2&-3\\1&0\\4&2\end{array}\right]-\left[\begin{array}{ccc}6&-1\\3&-2\\0&1\end{array}\right]$

   $\left[\begin{array}{ccc}-2-6&-3-(-1)\\1-3&0-(-2)\\4-0&2-1\end{array}\right]$

   $\left[\begin{array}{ccc}-2-6&-3+1\\1-3&0+2\\4-0&2-1\end{array}\right]=\left[\begin{array}{ccc}-8&-2\\-2&2\\4&1\end{array}\right]$

***************************************************************************************

c) C - A + B

   $\left[\begin{array}{ccc}6&-1\\3&-2\\0&1\end{array}\right]-\left[\begin{array}{ccc}1&5\\2&4\\-1&3\end{array}\right]+\left[\begin{array}{ccc}-2&-3\\1&0\\4&2\end{array}\right]$

   $\left[\begin{array}{ccc}6-1+(-2)&-1-5+(-3)\\3-2+1&-2-4+0\\0-(-1)+4&1-3+2\end{array}\right]$

   $\left[\begin{array}{ccc}6-1-2&-1-5-3\\3-2+1&-2-4+0\\0+1+4&1-3+2\end{array}\right]=\left[\begin{array}{ccc}3&-9\\2&-6\\5&0\end{array}\right]$

************************************************************************************

d) Vamos calcular primeiro a matriz transposta de A e C.

   Matriz transposta é uma matriz resultante da troca ordenadamente

   de linhas pelas colunas de outra matriz. Então:

   $A=\left[\begin{array}{ccc}1&5\\2&4\\-1&3\end{array}\right]$ → $A^{t}=\left[\begin{array}{ccc}1&2&-1\\5&4&3\\\end{array}\right]$

   $C=\left[\begin{array}{ccc}6&-1\\3&-2\\0&1\end{array}\right]$ → $C^{t}=\left[\begin{array}{ccc}6&3&0\\-1&-2&1\\\end{array}\right]$

   $A^{t}-C^{t}$

   $\left[\begin{array}{ccc}1&2&-1\\5&4&3\\\end{array}\right]-\left[\begin{array}{ccc}6&3&0\\-1&-2&1\\\end{array}\right]$

   $\left[\begin{array}{ccc}1-6&2-3&-1-0\\5-(-1)&4-(-2)&3-1\\\end{array}\right]$

   $\left[\begin{array}{ccc}1-6&2-3&-1-0\\5+1&4+2&3-1\\\end{array}\right]=\left[\begin{array}{ccc}-5&-1&-1\\6&6&2\\\end{array}\right]$