Question

Gente, me ajudem por favor. Eu preciso disso pra hoje 06/05

A) x²-x-b=0

B) bx²+3x+4=-8​

Answer 1

Resposta:

$A)\\ \\ x^{2} -x-b=0\\ \\ coeficientes:a=1,b=-1,c=-b\\ \\ x=\frac{-b+-\sqrt{b^{2} -4.a.c} }{2.a} \\ \\ x=\frac{-(-1)+-\sqrt{(-1)^{2}-4.1.-b} }{2.1} \\ \\ x=\frac{1+-\sqrt{1+4b} }{2} \\ \\ x'=\frac{1+\sqrt{1+4b} }{2} \\ \\ x''=\frac{1-\sqrt{1+4b} }{2}$

$B)\\ \\ bx^{2} +3x+4=-8\\ \\ bx^{2} +3x+4+8=0\\ \\ bx^{2} +3x+12=0\\ \\ coeficientes:a=b,b=3,c=12\\ \\ x=\frac{-b+-\sqrt{b^{2}-4.a.c } }{2.a} \\ \\ x=\frac{-3+-\sqrt{3^{2}-4.b.12 } }{2b} \\ \\ x=\frac{-3+-\sqrt{9-48b} }{2b} \\ \\ x'=\frac{-3+\sqrt{9-48b} }{2b} \\ \\ x''=\frac{-3-\sqrt{9-48b} }{2b}$