Matemática, perguntado por josielysantos994, 9 meses atrás

Gente me ajudem por favor

Anexos:

Soluções para a tarefa

Respondido por victorhugo1362
2

Explicação passo-a-passo:

1 )

\sf \left \{ {{ x+ y=10} \atop {x - y = 2}}

=>Valor de X

\sf 2x = 12

\sf x =  \frac{12}{2}

\boxed{\boxed{\sf x =  6}}

=>Valor de Y

</strong><strong>\</strong><strong>s</strong><strong>f</strong><strong> </strong><strong>x</strong><strong> + y = 10

</strong><strong>\</strong><strong>s</strong><strong>f</strong><strong> </strong><strong>6 + y = 10

</strong><strong>\</strong><strong>s</strong><strong>f</strong><strong> </strong><strong>y</strong><strong> = 10 - 6

</strong><strong>\</strong><strong>b</strong><strong>o</strong><strong>x</strong><strong>e</strong><strong>d</strong><strong>{</strong><strong>\</strong><strong>b</strong><strong>o</strong><strong>x</strong><strong>e</strong><strong>d</strong><strong>{</strong><strong>\</strong><strong>s</strong><strong>f</strong><strong> </strong><strong>y</strong><strong> = 4</strong><strong>}</strong><strong>}</strong><strong>

( x , y ) = ( 6 ; 4 )

2 )

\sf \left \{ {{x + y=6} \atop {x + y = 4}}

\left \{ {{x + y = 6} \atop { - x  - y =  - 4}} \right

0 = 2

( x , y ) e ∅

SPD pois ele é determinado

Espero ter ajudado !!!

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