Question

gente, me ajudem por favor!!!!!​

Answer 1

Resposta:

5- 8 e a diagonal (d)

(L) e o lado do quadrado

$\frac{d}{L}$ = $\sqrt{2}$

logo:

L $\sqrt{2}$ = d

L=$\frac{d}{\sqrt{2} }$

L= $d\frac{\sqrt{2} }{2}$

L = 8$\frac{\sqrt{2} }{2} = 4\sqrt{2}$

6-

$\frac{h}{L}= \frac{\sqrt{3} }{2} \\\\\frac{8}{L} = \frac{\sqrt{3} }{2}\\multiplique\\\\16= L \sqrt{3} \\\\racionalize\\\\\frac{16\sqrt{3} }{3} = L$

7-

$\frac{2\pi r }{D} = \pi , logo, 2r = D\\\\2\pi r = 8\\\\r=\frac{8}{2\pi } \\\\r=\frac{4}{\pi }$