Question

gente me ajudem pfv


$4a - 98 = \frac{a}{2}$

$3 (x - 7) + 25 = \frac{x + 9}{5}$

$- 5m + 13 = 4(8 - m)$

$3y + 87 = 3 + 87y$


$2x + 3( {4x}^{2} + x- 1) = 12 {x}^{2}$
a professora que o cálculo tbm, socorro​

Answer 1

Explicação passo-a-passo:

$4a - 98 = \frac{a}{2}$

$8a - 196 = a$

$8a - a = 196$

$7a = 196$

$a = \frac{196}{7} = 28$

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$3(x - 7) + 25 = \frac{x + 9}{5}$

$3x - 21 + 25 = \frac{x + 9}{5}$

$15x + 20 = x + 9$

$15x - x = 9 - 20$

$14x = - 11$

$x = - \frac{11}{14}$

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$- 5m + 13 = 4(8 - m)$

$- 5m + 13 = 32 - 4m$

$- 5m + 4m = 32 - 13$

$- x = 19( - 1)$

$x = - 19$

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$3y + 87 = 3 + 87y$

$87y - 3y = 87 - 3$

$84y = 84$

$y = 84 \div 84$

$y = 1$

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$2x + 3( {4x}^{2} + x - 1) = 12 {x}^{2}$

$2x + 12 {x}^{2} + 3x - 3 = 12 {x}^{2}$

$12 {x}^{2} - 12 {x}^{2} + 5x = 3$

$x = \frac{3}{5}$

Bons Estudos Jovem!!